C++|一个函数为什么调用一次正常,调用多次会出错?
liebian365 2024-10-22 15:34 6 浏览 0 评论
看下面小程序及输出:
#include <string> #include <time.h> #include <stdio.h> #include <stdlib.h> #include <string.h> using namespace std; string jieqi[] = {"小寒","大寒", "立春","雨水","惊蛰","春分","清明","谷雨", "立夏","小满","芒种","夏至","小暑","大暑", "立秋","处暑","白露","秋分","寒露","霜降", "立冬","小雪","大雪","冬至"}; int jieqiDiffMinu[] = {0,21208, // 1900年的各个节气到小寒的分钟数 42467,63836,85337,107014,128867,150921, 173149,195551,218072,240693,263343,285989, 308563,331033,353350,375494,397447,419210, 440795,462224,483532,504758}; unsigned int LunarCalendarDay; unsigned int LunarCalendarTable[] = // 199 { 0x04AE53,0x0A5748,0x5526BD,0x0D2650,0x0D9544,0x46AAB9,0x056A4D,0x09AD42,0x24AEB6,0x04AE4A,/*1901-1910*/ 0x6A4DBE,0x0A4D52,0x0D2546,0x5D52BA,0x0B544E,0x0D6A43,0x296D37,0x095B4B,0x749BC1,0x049754,/*1911-1920*/ 0x0A4B48,0x5B25BC,0x06A550,0x06D445,0x4ADAB8,0x02B64D,0x095742,0x2497B7,0x04974A,0x664B3E,/*1921-1930*/ 0x0D4A51,0x0EA546,0x56D4BA,0x05AD4E,0x02B644,0x393738,0x092E4B,0x7C96BF,0x0C9553,0x0D4A48,/*1931-1940*/ 0x6DA53B,0x0B554F,0x056A45,0x4AADB9,0x025D4D,0x092D42,0x2C95B6,0x0A954A,0x7B4ABD,0x06CA51,/*1941-1950*/ 0x0B5546,0x555ABB,0x04DA4E,0x0A5B43,0x352BB8,0x052B4C,0x8A953F,0x0E9552,0x06AA48,0x6AD53C,/*1951-1960*/ 0x0AB54F,0x04B645,0x4A5739,0x0A574D,0x052642,0x3E9335,0x0D9549,0x75AABE,0x056A51,0x096D46,/*1961-1970*/ 0x54AEBB,0x04AD4F,0x0A4D43,0x4D26B7,0x0D254B,0x8D52BF,0x0B5452,0x0B6A47,0x696D3C,0x095B50,/*1971-1980*/ 0x049B45,0x4A4BB9,0x0A4B4D,0xAB25C2,0x06A554,0x06D449,0x6ADA3D,0x0AB651,0x093746,0x5497BB,/*1981-1990*/ 0x04974F,0x064B44,0x36A537,0x0EA54A,0x86B2BF,0x05AC53,0x0AB647,0x5936BC,0x092E50,0x0C9645,/*1991-2000*/ 0x4D4AB8,0x0D4A4C,0x0DA541,0x25AAB6,0x056A49,0x7AADBD,0x025D52,0x092D47,0x5C95BA,0x0A954E,/*2001-2010*/ 0x0B4A43,0x4B5537,0x0AD54A,0x955ABF,0x04BA53,0x0A5B48,0x652BBC,0x052B50,0x0A9345,0x474AB9,/*2011-2020*/ 0x06AA4C,0x0AD541,0x24DAB6,0x04B64A,0x69573D,0x0A4E51,0x0D2646,0x5E933A,0x0D534D,0x05AA43,/*2021-2030*/ 0x36B537,0x096D4B,0xB4AEBF,0x04AD53,0x0A4D48,0x6D25BC,0x0D254F,0x0D5244,0x5DAA38,0x0B5A4C,/*2031-2040*/ 0x056D41,0x24ADB6,0x049B4A,0x7A4BBE,0x0A4B51,0x0AA546,0x5B52BA,0x06D24E,0x0ADA42,0x355B37,/*2041-2050*/ 0x09374B,0x8497C1,0x049753,0x064B48,0x66A53C,0x0EA54F,0x06B244,0x4AB638,0x0AAE4C,0x092E42,/*2051-2060*/ 0x3C9735,0x0C9649,0x7D4ABD,0x0D4A51,0x0DA545,0x55AABA,0x056A4E,0x0A6D43,0x452EB7,0x052D4B,/*2061-2070*/ 0x8A95BF,0x0A9553,0x0B4A47,0x6B553B,0x0AD54F,0x055A45,0x4A5D38,0x0A5B4C,0x052B42,0x3A93B6,/*2071-2080*/ 0x069349,0x7729BD,0x06AA51,0x0AD546,0x54DABA,0x04B64E,0x0A5743,0x452738,0x0D264A,0x8E933E,/*2081-2090*/ 0x0D5252,0x0DAA47,0x66B53B,0x056D4F,0x04AE45,0x4A4EB9,0x0A4D4C,0x0D1541,0x2D92B5 /*2091-2099*/ }; int MonthAdd[12] = {0,31,59,90,120,151,181,212,243,273,304,334}; bool isLeapYear(int y) { return (y%4==0&&y%100!=0 || y%400==0); } int sTerm(int y,int n) { // 某年的第n个节气为几日(从0小寒起算) double ms = 31556925974.7*(y-1900); // 31556925974.7是一年(365.2422)的豪秒数 ms += jieqiDiffMinu[n]*60*1000.0; // 1分钟60000毫秒,sTermInfo记录的是分钟数 // 1000.0处理溢出 ms += ((6*24+2)*60+5)*60*1000; // 1900年1月6号2时5分为小寒 for(int i=1900; i<y; i++) { for(int k=1;k<=365;k++) ms-=24*3600000; if(isLeapYear(i)) ms-=24*3600000; //ms-=366*24*3600000; // integral constant overflow,可以加.0 } double ds = ms/(24*3600000); int monDays[] = {31,28,31,30,31,30,31,31,30,31,30,31}; if(isLeapYear(y)) monDays[1] = 29; for(int j=0;j<12;j++) if(ds>monDays[j]) ds-=monDays[j]; return(ds); } string Gan[]={"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"}; string Zhi[]={"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"}; string Shu[]={"鼠","牛","虎","免","龙","蛇","马","羊","猴","鸡","狗","猪"}; /* 10天干=(y%10)-3),如果小于0,再加10(y是年份); 12地支=(y%12)-3),如果小于0,再加12; 例:求公元2018年的干支? 年干=8-3 =5 =戊(2018/10的余数是8); 年支=2-3+12=11=戌(2018/12的余数是2); */ int gan(int y) { int g = (y%10)-3; if(g<=0) g+=10; return g; } int zhi(int y) { int z = (y%12)-3; if(z<=0) z+=12; return z; } int LunarCalendar(int year,int month,int day) { int Spring_NY; // 记录春节离当年元旦的天数。 int Sun_NY; // 记录阳历日离当年元旦的天数。 if ( ((LunarCalendarTable[year-1901] & 0x0060) >> 5) == 1) Spring_NY = (LunarCalendarTable[year-1901] & 0x001F) - 1; else Spring_NY = (LunarCalendarTable[year-1901] & 0x001F) - 1 + 31; Sun_NY = MonthAdd[month-1] + day - 1; if ( (!(year % 4)) && (month > 2)) Sun_NY++; int StaticDayCount; // 记录大小月的天数29或30 int index ; // 记录从哪个月开始来计算。 int flag; // 对闰月的特殊处理,判断阳历日在春节前还是春节后 if (Sun_NY >= Spring_NY) // 阳历日在春节后(含春节那天) { Sun_NY -= Spring_NY; month = 1; index = 1; flag = 0; if ( ( LunarCalendarTable[year - 1901] & (0x80000 >> (index-1)) ) ==0) StaticDayCount = 29; else StaticDayCount = 30; while (Sun_NY >= StaticDayCount) { Sun_NY -= StaticDayCount; index++; if (month == ((LunarCalendarTable[year - 1901] & 0xF00000) >> 20) ) { flag = ~flag; if (flag == 0) month++; } else month++; if ( ( LunarCalendarTable[year - 1901] & (0x80000 >> (index-1)) ) ==0) StaticDayCount=29; else StaticDayCount=30; } day = Sun_NY + 1; } else // 阳历日在春节前 { Spring_NY -= Sun_NY; year--; month = 12; if ( ((LunarCalendarTable[year - 1901] & 0xF00000) >> 20) == 0) index = 12; else index = 13; flag = 0; if ( ( LunarCalendarTable[year - 1901] & (0x80000 >> (index-1)) ) ==0) StaticDayCount = 29; else StaticDayCount = 30; while (Spring_NY > StaticDayCount) { Spring_NY -= StaticDayCount; index--; if (flag == 0) month--; if (month == ((LunarCalendarTable[year - 1901] & 0xF00000) >> 20)) flag = ~flag; if ( ( LunarCalendarTable[year - 1901] & (0x80000 >> (index-1)) ) ==0) StaticDayCount = 29; else StaticDayCount = 30; } day = StaticDayCount - Spring_NY + 1; } LunarCalendarDay |= day; LunarCalendarDay |= (month << 6); if (month == ((LunarCalendarTable[year - 1901] & 0xF00000) >> 20)) return 1; else return 0; } // 用动态内存存储以下下级也是内存访问错误 string LunarMonthDay(unsigned int year,unsigned int month, unsigned int day) { const char* ChDay[] = {"*","初一","初二","初三","初四","初五", "初六","初七","初八","初九","初十", "十一","十二","十三","十四","十五", "十六","十七","十八","十九","二十", "廿一","廿二","廿三","廿四","廿五", "廿六","廿七","廿八","廿九","三十"}; const char* ChMonth[] = {"*","正","二","三","四","五","六","七","八","九","十","十一","腊"}; char str[13] = ""; if (LunarCalendar(year,month,day)) { strcat(str,"闰"); strcat(str,ChMonth[(LunarCalendarDay & 0x3C0) >> 6]); } else strcat(str,ChMonth[(LunarCalendarDay & 0x3C0) >> 6]); strcat(str,"月"); strcat(str,ChDay[LunarCalendarDay & 0x3F]); string strs = str; return strs; } void jieqiYear(int y) { printf("%d(%s%s%s年)的节气和对应公历日期和农历日期:\n", y, Gan[gan(y)-1].c_str(), Zhi[zhi(y)-1].c_str(), Shu[zhi(y)-1].c_str()); for(int m=0;m<12;m++) { printf("%2d月: ",m+1); int jie = sTerm(y,m*2); printf("%s:%d %s ",jieqi[m*2].c_str(),jie, LunarMonthDay(y,m+1,jie).c_str()); int qi = sTerm(y,m*2+1); printf("%s:%d %s\n",jieqi[m*2+1].c_str(),qi, LunarMonthDay(y,m+1,qi).c_str()); if((m+1)%3==0) printf("\n"); } } main() { #if 1 long t = time(NULL); struct tm* Local = localtime(&t); int y = Local->tm_year + 1900; //for(int i = 1;i<12;i++) // 出错 jieqiYear(y); #else //printf("\n%s\n",LunarMonthDay(1977,4,19).c_str()); printf("请输入年份即输出对应各月的节气和日期:"); int y = 2019; //scanf("%d",&y); jieqiYear(y); #endif system("pause"); }
有问题的函数可以追溯到LunarCalendar(),是因为其修改了全局变量LunarCalendarDay,该变量的后六位保存的是日期信息(几日),剩下的位保存的是月份信息。且该全局变量在其它函数中有用做数组下标,首次修改可控,多次修改就不可控了。这就是全局变量的危险性,特别是当其用做数组下标,且程序较复杂时。(LunarCalendarDay()返回的是农历是否是闰年的信息)
对上面函数可简单将全局变量更改为输出的引用参数即可:
#include <string> #include <time.h> #include <stdio.h> #include <stdlib.h> #include <string.h> using namespace std; string jieqi[] = {"小寒","大寒", "立春","雨水","惊蛰","春分","清明","谷雨", "立夏","小满","芒种","夏至","小暑","大暑", "立秋","处暑","白露","秋分","寒露","霜降", "立冬","小雪","大雪","冬至"}; int jieqiDiffMinu[] = {0,21208, // 1900年的各个节气到小寒的分钟数 42467,63836,85337,107014,128867,150921, 173149,195551,218072,240693,263343,285989, 308563,331033,353350,375494,397447,419210, 440795,462224,483532,504758}; unsigned int LunarCalendarTable[] = // 199 { 0x04AE53,0x0A5748,0x5526BD,0x0D2650,0x0D9544,0x46AAB9,0x056A4D,0x09AD42,0x24AEB6,0x04AE4A,/*1901-1910*/ 0x6A4DBE,0x0A4D52,0x0D2546,0x5D52BA,0x0B544E,0x0D6A43,0x296D37,0x095B4B,0x749BC1,0x049754,/*1911-1920*/ 0x0A4B48,0x5B25BC,0x06A550,0x06D445,0x4ADAB8,0x02B64D,0x095742,0x2497B7,0x04974A,0x664B3E,/*1921-1930*/ 0x0D4A51,0x0EA546,0x56D4BA,0x05AD4E,0x02B644,0x393738,0x092E4B,0x7C96BF,0x0C9553,0x0D4A48,/*1931-1940*/ 0x6DA53B,0x0B554F,0x056A45,0x4AADB9,0x025D4D,0x092D42,0x2C95B6,0x0A954A,0x7B4ABD,0x06CA51,/*1941-1950*/ 0x0B5546,0x555ABB,0x04DA4E,0x0A5B43,0x352BB8,0x052B4C,0x8A953F,0x0E9552,0x06AA48,0x6AD53C,/*1951-1960*/ 0x0AB54F,0x04B645,0x4A5739,0x0A574D,0x052642,0x3E9335,0x0D9549,0x75AABE,0x056A51,0x096D46,/*1961-1970*/ 0x54AEBB,0x04AD4F,0x0A4D43,0x4D26B7,0x0D254B,0x8D52BF,0x0B5452,0x0B6A47,0x696D3C,0x095B50,/*1971-1980*/ 0x049B45,0x4A4BB9,0x0A4B4D,0xAB25C2,0x06A554,0x06D449,0x6ADA3D,0x0AB651,0x093746,0x5497BB,/*1981-1990*/ 0x04974F,0x064B44,0x36A537,0x0EA54A,0x86B2BF,0x05AC53,0x0AB647,0x5936BC,0x092E50,0x0C9645,/*1991-2000*/ 0x4D4AB8,0x0D4A4C,0x0DA541,0x25AAB6,0x056A49,0x7AADBD,0x025D52,0x092D47,0x5C95BA,0x0A954E,/*2001-2010*/ 0x0B4A43,0x4B5537,0x0AD54A,0x955ABF,0x04BA53,0x0A5B48,0x652BBC,0x052B50,0x0A9345,0x474AB9,/*2011-2020*/ 0x06AA4C,0x0AD541,0x24DAB6,0x04B64A,0x69573D,0x0A4E51,0x0D2646,0x5E933A,0x0D534D,0x05AA43,/*2021-2030*/ 0x36B537,0x096D4B,0xB4AEBF,0x04AD53,0x0A4D48,0x6D25BC,0x0D254F,0x0D5244,0x5DAA38,0x0B5A4C,/*2031-2040*/ 0x056D41,0x24ADB6,0x049B4A,0x7A4BBE,0x0A4B51,0x0AA546,0x5B52BA,0x06D24E,0x0ADA42,0x355B37,/*2041-2050*/ 0x09374B,0x8497C1,0x049753,0x064B48,0x66A53C,0x0EA54F,0x06B244,0x4AB638,0x0AAE4C,0x092E42,/*2051-2060*/ 0x3C9735,0x0C9649,0x7D4ABD,0x0D4A51,0x0DA545,0x55AABA,0x056A4E,0x0A6D43,0x452EB7,0x052D4B,/*2061-2070*/ 0x8A95BF,0x0A9553,0x0B4A47,0x6B553B,0x0AD54F,0x055A45,0x4A5D38,0x0A5B4C,0x052B42,0x3A93B6,/*2071-2080*/ 0x069349,0x7729BD,0x06AA51,0x0AD546,0x54DABA,0x04B64E,0x0A5743,0x452738,0x0D264A,0x8E933E,/*2081-2090*/ 0x0D5252,0x0DAA47,0x66B53B,0x056D4F,0x04AE45,0x4A4EB9,0x0A4D4C,0x0D1541,0x2D92B5 /*2091-2099*/ }; int MonthAdd[12] = {0,31,59,90,120,151,181,212,243,273,304,334}; bool isLeapYear(int y) { return (y%4==0&&y%100!=0 || y%400==0); } int sTerm(int y,int n) { // 某年的第n个节气为几日(从0小寒起算) double ms = 31556925974.7*(y-1900); // 31556925974.7是一年(365.2422)的豪秒数 ms += jieqiDiffMinu[n]*60*1000.0; // 1分钟60000毫秒,sTermInfo记录的是分钟数 // 1000.0处理溢出 ms += ((6*24+2)*60+5)*60*1000; // 1900年1月6号2时5分为小寒 //ms -= 6*3600000; // adjust ,error for(int i=1900; i<y; i++) { for(int k=1;k<=365;k++) ms-=24*3600000; if(isLeapYear(i)) ms-=24*3600000; //ms-=366*24*3600000; // integral constant overflow } double ds = ms/(24*3600000); int monDays[] = {31,28,31,30,31,30,31,31,30,31,30,31}; if(isLeapYear(y)) monDays[1] = 29; for(int j=0;j<12;j++) if(ds>monDays[j]) ds-=monDays[j]; return(ds); } // 2019年夏至时间 6月21日 23:54:09 ds 22.05 string Gan[]={"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"}; string Zhi[]={"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"}; string Shu[]={"鼠","牛","虎","免","龙","蛇","马","羊","猴","鸡","狗","猪"}; /* 10天干=(y%10)-3),如果小于0,再加10(y是年份); 12地支=(y%12)-3),如果小于0,再加12; 例:求公元2018年的干支? 年干=8-3 =5 =戊(2018/10的余数是8); 年支=2-3+12=11=戌(2018/12的余数是2); */ int gan(int y) { int g = (y%10)-3; if(g<=0) g+=10; return g; } int zhi(int y) { int z = (y%12)-3; if(z<=0) z+=12; return z; } int LunarCalendar(int year,int month,int day, unsigned int& LunarCalendarDay) { int Spring_NY; // 记录春节离当年元旦的天数。 int Sun_NY; // 记录阳历日离当年元旦的天数。 if ( ((LunarCalendarTable[year-1901] & 0x0060) >> 5) == 1) Spring_NY = (LunarCalendarTable[year-1901] & 0x001F) - 1; else Spring_NY = (LunarCalendarTable[year-1901] & 0x001F) - 1 + 31; Sun_NY = MonthAdd[month-1] + day - 1; if ( (!(year % 4)) && (month > 2)) Sun_NY++; int StaticDayCount; // 记录大小月的天数29或30 int index ; // 记录从哪个月开始来计算。 int flag; // 对闰月的特殊处理,判断阳历日在春节前还是春节后 if (Sun_NY >= Spring_NY) // 阳历日在春节后(含春节那天) { Sun_NY -= Spring_NY; month = 1; index = 1; flag = 0; if ( ( LunarCalendarTable[year - 1901] & (0x80000 >> (index-1)) ) ==0) StaticDayCount = 29; else StaticDayCount = 30; while (Sun_NY >= StaticDayCount) { Sun_NY -= StaticDayCount; index++; if (month == ((LunarCalendarTable[year - 1901] & 0xF00000) >> 20) ) { flag = ~flag; if (flag == 0) month++; } else month++; if ( ( LunarCalendarTable[year - 1901] & (0x80000 >> (index-1)) ) ==0) StaticDayCount=29; else StaticDayCount=30; } day = Sun_NY + 1; } else // 阳历日在春节前 { Spring_NY -= Sun_NY; year--; month = 12; if ( ((LunarCalendarTable[year - 1901] & 0xF00000) >> 20) == 0) index = 12; else index = 13; flag = 0; if ( ( LunarCalendarTable[year - 1901] & (0x80000 >> (index-1)) ) ==0) StaticDayCount = 29; else StaticDayCount = 30; while (Spring_NY > StaticDayCount) { Spring_NY -= StaticDayCount; index--; if (flag == 0) month--; if (month == ((LunarCalendarTable[year - 1901] & 0xF00000) >> 20)) flag = ~flag; if ( ( LunarCalendarTable[year - 1901] & (0x80000 >> (index-1)) ) ==0) StaticDayCount = 29; else StaticDayCount = 30; } day = StaticDayCount - Spring_NY + 1; } LunarCalendarDay |= day; LunarCalendarDay |= (month << 6); // LunarCalendarDay低6位存储day,其余位存储month if (month == ((LunarCalendarTable[year - 1901] & 0xF00000) >> 20)) return 1; // 是否是闰年 else return 0; } int flag2 = 0; // 辅助处理闰年,农历闰年时,两个月三个节气 string LunarMonthDay(unsigned int year,unsigned int month, unsigned int day) { unsigned int LunarCalendarDay=0; const char* ChDay[] = {"*","初一","初二","初三","初四","初五", "初六","初七","初八","初九","初十", "十一","十二","十三","十四","十五", "十六","十七","十八","十九","二十", "廿一","廿二","廿三","廿四","廿五", "廿六","廿七","廿八","廿九","三十"}; const char* ChMonth[] = {"*","正","二","三","四","五","六","七","八","九","十","十一","腊"}; char str[13] = ""; if (LunarCalendar(year,month,day,LunarCalendarDay)) { if(flag2 > 0) strcat(str,"闰"); flag2++; strcat(str,ChMonth[(LunarCalendarDay & 0x3C0) >> 6]); } else strcat(str,ChMonth[(LunarCalendarDay & 0x3C0) >> 6]); strcat(str,"月"); strcat(str,ChDay[LunarCalendarDay & 0x3F]); string strs = str; return strs; } void jieqiYear(int y) { printf("\n%d(%s%s%s年)的节气和对应公历日期和农历日期:\n", y, Gan[gan(y)-1].c_str(), Zhi[zhi(y)-1].c_str(), Shu[zhi(y)-1].c_str()); //int m = 5; for(int m=0;m<12;m++) { int jie = sTerm(y,m*2); printf("%s:%2d月%d日 %12s ",jieqi[m*2].c_str(),m+1,jie, LunarMonthDay(y,m+1,jie).c_str()); int qi = sTerm(y,m*2+1); printf("%s:%2d月%d %12s\n",jieqi[m*2+1].c_str(),m+1,qi, LunarMonthDay(y,m+1,qi).c_str()); if((m+1)%3==0) printf("\n"); } } main() { #if 1 long t = time(NULL); struct tm* Local = localtime(&t); int y = Local->tm_year + 1900; //for(int i = 1;i<12;i++) // 出错 jieqiYear(y); #else //printf("\n%s\n",LunarMonthDay(1977,4,19).c_str()); printf("请输入年份即输出对应各月的节气和日期:"); int y = 2019; //scanf("%d",&y); jieqiYear(y) #endif system("pause"); }
-End-
相关推荐
- 快递查询教程,批量查询物流,一键管理快递
-
作为商家,每天需要查询许许多多的快递单号,面对不同的快递公司,有没有简单一点的物流查询方法呢?小编的回答当然是有的,下面随小编一起来试试这个新技巧。需要哪些工具?安装一个快递批量查询高手快递单号怎么快...
- 一键自动查询所有快递的物流信息 支持圆通、韵达等多家快递
-
对于各位商家来说拥有一个好的快递软件,能够有效的提高自己的工作效率,在管理快递单号的时候都需要对单号进行表格整理,那怎么样能够快速的查询所有单号信息,并自动生成表格呢?1、其实方法很简单,我们不需要一...
- 快递查询单号查询,怎么查物流到哪了
-
输入单号怎么查快递到哪里去了呢?今天小编给大家分享一个新的技巧,它支持多家快递,一次能查询多个单号物流,还可对查询到的物流进行分析、筛选以及导出,下面一起来试试。需要哪些工具?安装一个快递批量查询高手...
- 3分钟查询物流,教你一键批量查询全部物流信息
-
很多朋友在问,如何在短时间内把单号的物流信息查询出来,查询完成后筛选已签收件、筛选未签收件,今天小编就分享一款物流查询神器,感兴趣的朋友接着往下看。第一步,运行【快递批量查询高手】在主界面中点击【添...
- 快递单号查询,一次性查询全部物流信息
-
现在各种快递的查询方式,各有各的好,各有各的劣,总的来说,还是有比较方便的。今天小编就给大家分享一个新的技巧,支持多家快递,一次能查询多个单号的物流,还能对查询到的物流进行分析、筛选以及导出,下面一起...
- 快递查询工具,批量查询多个快递快递单号的物流状态、签收时间
-
最近有朋友在问,怎么快速查询单号的物流信息呢?除了官网,还有没有更简单的方法呢?小编的回答当然是有的,下面一起来看看。需要哪些工具?安装一个快递批量查询高手多个京东的快递单号怎么快速查询?进入快递批量...
- 快递查询软件,自动识别查询快递单号查询方法
-
当你拥有多个快递单号的时候,该如何快速查询物流信息?比如单号没有快递公司时,又该如何自动识别再去查询呢?不知道如何操作的宝贝们,下面随小编一起来试试。需要哪些工具?安装一个快递批量查询高手快递单号若干...
- 教你怎样查询快递查询单号并保存物流信息
-
商家发货,快递揽收后,一般会直接手动复制到官网上一个个查询物流,那么久而久之,就会觉得查询变得特别繁琐,今天小编给大家分享一个新的技巧,下面一起来试试。教程之前,我们来预览一下用快递批量查询高手...
- 简单几步骤查询所有快递物流信息
-
在高峰期订单量大的时候,可能需要一双手当十双手去查询快递物流,但是由于逐一去查询,效率极低,追踪困难。那么今天小编给大家分享一个新的技巧,一次能查询多个快递单号的物流,下面一起来学习一下,希望能给大家...
- 物流单号查询,如何查询快递信息,按最后更新时间搜索需要的单号
-
最近有很多朋友在问,如何通过快递单号查询物流信息,并按最后更新时间搜索出需要的单号呢?下面随小编一起来试试吧。需要哪些工具?安装一个快递批量查询高手快递单号若干怎么快速查询?运行【快递批量查询高手】...
- 连续保存新单号功能解析,导入单号查询并自动识别批量查快递信息
-
快递查询已经成为我们日常生活中不可或缺的一部分。然而,面对海量的快递单号,如何高效、准确地查询每一个快递的物流信息,成为了许多人头疼的问题。幸运的是,随着科技的进步,一款名为“快递批量查询高手”的软件...
- 快递查询教程,快递单号查询,筛选更新量为1的单号
-
最近有很多朋友在问,怎么快速查询快递单号的物流,并筛选出更新量为1的单号呢?今天小编给大家分享一个新方法,一起来试试吧。需要哪些工具?安装一个快递批量查询高手多个快递单号怎么快速查询?运行【快递批量查...
- 掌握批量查询快递动态的技巧,一键查找无信息记录的两种方法解析
-
在快节奏的商业环境中,高效的物流查询是确保业务顺畅运行的关键。作为快递查询达人,我深知时间的宝贵,因此,今天我将向大家介绍一款强大的工具——快递批量查询高手软件。这款软件能够帮助你批量查询快递动态,一...
- 从复杂到简单的单号查询,一键清除单号中的符号并批量查快递信息
-
在繁忙的商务与日常生活中,快递查询已成为不可或缺的一环。然而,面对海量的单号,逐一查询不仅耗时费力,还容易出错。现在,有了快递批量查询高手软件,一切变得简单明了。只需一键,即可搞定单号查询,一键处理单...
- 物流单号查询,在哪里查询快递
-
如果在快递单号多的情况,你还在一个个复制粘贴到官网上手动查询,是一件非常麻烦的事情。于是乎今天小编给大家分享一个新的技巧,下面一起来试试。需要哪些工具?安装一个快递批量查询高手快递单号怎么快速查询?...
你 发表评论:
欢迎- 一周热门
- 最近发表
- 标签列表
-
- wireshark怎么抓包 (75)
- qt sleep (64)
- cs1.6指令代码大全 (55)
- factory-method (60)
- sqlite3_bind_blob (52)
- hibernate update (63)
- c++ base64 (70)
- nc 命令 (52)
- wm_close (51)
- epollin (51)
- sqlca.sqlcode (57)
- lua ipairs (60)
- tv_usec (64)
- 命令行进入文件夹 (53)
- postgresql array (57)
- statfs函数 (57)
- .project文件 (54)
- lua require (56)
- for_each (67)
- c#工厂模式 (57)
- wxsqlite3 (66)
- dmesg -c (58)
- fopen参数 (53)
- tar -zxvf -c (55)
- 速递查询 (52)